A) \[x=\frac{3}{4}\]
B) \[x=\frac{2}{3}\]
C) \[x=\frac{5}{6}\]
D) \[x=\frac{3}{2}\]
Correct Answer: D
Solution :
(d) \[{{81}^{2x}}={{\left( 72 \right)}^{2}}={{\left( 81\times 9 \right)}^{2}}={{\left( 81 \right)}^{2}}\times {{9}^{2}}\] \[={{\left( 81 \right)}^{2}}\times 81={{81}^{3}}=2x=3\Rightarrow x=\frac{3}{2}.\]
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