A) 0
B) \[-\]1
C) 1
D) \[{{x}^{a+b}}\]
Correct Answer: C
Solution :
(c) \[\frac{1}{1+{{x}^{a-b}}}+\frac{1}{1+{{x}^{b-a}}}\] \[{{x}^{a-b}}=y\Rightarrow {{x}^{b-a}}=\frac{1}{y}\] \[=\frac{1}{1+y}+\frac{1}{\frac{1}{1+y}}=\frac{1}{1+y}+\frac{y}{1+y}=\frac{1+y}{1+y}=1.\]
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