7th Class Mathematics Exponents and Power Question Bank Exponents and Powers

  • question_answer
    Simplify \[\frac{{{(9{{m}^{2}})}^{1/3}}}{{{6}^{4}}}\times \frac{{{(4{{n}^{2}})}^{1/3}}}{5m}\].

    A)  \[\frac{1}{5}{{\left[ \frac{{{n}^{2}}}{m{{6}^{10}}} \right]}^{1/3}}\]             

    B)         \[\frac{1}{5}{{\left[ \frac{n}{{{m}^{2}}{{6}^{10}}} \right]}^{1/3}}\]

    C)  \[\frac{1}{5}{{\left[ \frac{{{n}^{2}}}{m{{6}^{-10}}} \right]}^{1/3}}\]         

    D)         \[\frac{1}{5}{{\left[ \frac{{{n}^{2}}}{m{{6}^{10}}} \right]}^{2/3}}\]

    Correct Answer: A

    Solution :

     \[\frac{{{(9\,{{m}^{2}})}^{\frac{1}{3}}}}{{{6}^{4}}}\times \frac{{{(4\,{{n}^{2}})}^{\frac{1}{3}}}}{5\,m}\]\[=\frac{{{6}^{\frac{-10}{3}}}\,{{m}^{\frac{-1}{3}}}{{n}^{\frac{2}{3}}}}{5}=\frac{1}{5}{{\left[ \frac{{{n}^{2}}}{m{{6}^{10}}} \right]}^{\frac{1}{3}}}\]


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