A) 8
B) 32
C) \[{{2}^{-3}}\]
D) \[{{4}^{-3}}\]
Correct Answer: C
Solution :
(a) \[{{16}^{\frac{3}{4}}}={{\left( {{2}^{4}} \right)}^{3/4}}={{2}^{\bcancel{4\times \frac{3}{4}}}}\] \[={{2}^{3}}=8\]
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