A) 36
B) 32
C) \[{{3}^{\frac{27}{6}}}\]
D) None of these
Correct Answer: B
Solution :
(b) \[{{9}^{{}^{4}/{}_{3}}}\div {{\left( 81 \right)}^{^{{}^{2}/{}_{3}}}}={{9}^{^{{}^{4}/{}_{3}}}}\div {{\left( {{9}^{2}} \right)}^{{}^{2}/{}_{3}}}={{9}^{{}^{4}/{}_{3}}}\div {{9}^{{}^{4}/{}_{3}}}=1\] \[\therefore \]\[1\times {{3}^{{}^{3}/{}_{2}}}={{3}^{{}^{3}/{}_{2}}}\]You need to login to perform this action.
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