A) \[e\]
B) \[2\,e\]
C) \[3\,e\]
D) \[4\,e\]
Correct Answer: C
Solution :
\[1+\frac{3}{1!}+\frac{5}{2!}+\frac{7}{3!}+....\infty \] \[{{T}_{n}}=\frac{2n-1}{(n-1)!}=\frac{2(n-1)}{(n-1)!}+\frac{1}{(n-1)!}\] \[=\frac{2}{(n-2)!}+\frac{1}{(n-1)!}=2e+e=3e\].
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