• question_answer What is the sum of the powers of the prime factors in$72\times 192$? A)  5                                B)  7           C)  8                                D)  12

$72={{2}^{3}}\times {{3}^{2}}$ (Prime factors are 1, 2, 3); Prime factors are prime numbers $192={{2}^{6}}\times {{3}^{1}}$ (Prime factors are 1, 2, 3) $\therefore$  The required sum is$3+2+6+1=12$