A) 0
B) abc
C) 1/abc
D) None of these
Correct Answer: A
Solution :
\[\Delta =\frac{1}{a}[ab-ca]+1\left[ ca.\frac{1}{c}-\frac{1}{b}.ab \right]+bc\left[ \frac{1}{b}-\frac{1}{c} \right]\] Þ\[\Delta =(b-c)+1(a-a)+(c-b)\]Þ \[\Delta =0\].
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