A) 0
B) 1
C) - 1
D) None of these
Correct Answer: A
Solution :
\[\Delta \equiv \left| \,\begin{matrix} 2 & 2\omega & -{{\omega }^{2}} \\ 1 & 1 & 1 \\ 1 & -1 & 0 \\ \end{matrix}\, \right|=\left| \,\begin{matrix} 2+2\omega +2{{\omega }^{2}} & 2\omega & -{{\omega }^{2}} \\ 1+1-2 & 1 & 1 \\ 1-1-0 & -1 & 0 \\ \end{matrix}\, \right|\] \[({{C}_{1}}\to {{C}_{1}}+{{C}_{2}}-2{{C}_{3}})\] = \[\left| \,\begin{matrix} 0 & 2\omega & -{{\omega }^{2}} \\ 0 & 1 & 1 \\ 0 & -1 & 0 \\ \end{matrix}\, \right|\,=\,0\].
You need to login to perform this action.
You will be redirected in
3 sec
