A) \[F{{e}_{3}}{{({{P}_{2}}{{O}_{7}})}_{3}}\]
B) \[F{{e}_{4}}{{P}_{4}}{{O}_{14}}\]
C) \[F{{e}_{4}}{{({{P}_{2}}{{O}_{7}})}_{3}}\]
D) \[F{{e}_{3}}P{{O}_{4}}\]
Correct Answer: C
Solution :
As the formula of calcium pyrophosphate is \[C{{a}_{2}}{{P}_{2}}{{O}_{7}}\] means valency of pyrophosphate radical is ? 4 so formula of ferric pyrophosphate is \[F{{e}_{4}}{{\left( {{P}_{2}}{{O}_{7}} \right)}_{3}}\].
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