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10th Class Science Electricity and Circuits Question Bank Electricity

  • question_answer
    A voltmeter reading upto 100 mV is calibrated by a potentiometer. An emf of \[\text{1}.0\text{8}\] V is balanced across \[\text{5}\text{.4}\] m length of the wire. When voltmeter reading is \[0.\text{9}\] V, the balancing length is \[\text{4}\text{.55}\] m. The error in the voltmeter reading is

    A) \[-0.01\,V\]                         

    B)  \[-0.1\,V\]

    C)  \[-0.001\,V\]          

    D)         \[0\,V\]

    Correct Answer: A

    Solution :

                    \[K=\frac{V}{L}=\frac{1\cdot 08}{5\cdot 4}\]                 \[V'=Kl=\frac{1\cdot 08}{5\cdot 4}\times 4\cdot 55=0\cdot 91\,\,V\] Error          \[=0\cdot 9-0\cdot 91=-0.01\]


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