A) 384W
B) 576 W
C) 1500W
D) 1800W
Correct Answer: A
Solution :
Here if we apply formula\[\frac{{{V}^{2}}}{R}\], voltage should be carefully taken as the voltage that goes dropped across the\[6\Omega \], resistor\[(=120\times \frac{6}{15})\]. However, in series circuit it is always preferable to use formula\[{{I}^{2}}R\], because \[I\] throughout is same \[I=\frac{120}{6+9}=8\] \[\therefore \] \[P={{I}^{2}}R=64\times 6=384\]
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