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10th Class Science Electricity and Circuits Question Bank Electricity

  • question_answer
    A cell emf E is connected across a resistance R. The potential difference between the terminals of the cell is found to be V. The internal resistance of the cell must be

    A)  \[\frac{2(E-V)V}{R}\]    

    B)         \[\frac{2(E-V)R}{E}\]

    C)  \[\frac{(E-V)R}{V}\]        

    D)         \[(E-V)R\]

    Correct Answer: C

    Solution :

                    \[E-V\]  \[=\]      \[Ir\]                 \[V=IR\] Dividing, we get                \[\frac{E-V}{V}=\frac{r}{R}\]


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