Find the current passing through resistor.
A) 0.72 A
B) 0.80 A
C) 0.48 A
D) 0.62 A
Correct Answer: C
Solution :
\[\frac{1}{R}=\frac{1}{{{R}_{1}}}+\frac{1}{{{R}_{2}}}\](in parallel), \[\frac{1}{R}=\frac{1}{6}+\frac{1}{4}\] \[=\frac{4+6}{24}=\frac{10}{24}\]Total \[R=\frac{24}{10}=2.4\,\Omega \] \[Total\,I=1.2A,V=IR=1.2\times 2.4=2.88\,V\] \[V=I{{R}_{1}},I=\frac{2.88}{6}=0.48A\]
You need to login to perform this action.
You will be redirected in
3 sec
