A) \[1\times {{10}^{-12}}\]
B) \[2.1\times {{10}^{-4}}\]
C) \[1.25\times {{10}^{-6}}\]
D) \[1\times {{10}^{-14}}\]
Correct Answer: B
Solution :
\[{{K}_{a}}=C{{\alpha }^{2}}=0.2\times {{\left( \frac{32}{100} \right)}^{2}}=2.048\times {{10}^{-4}}\].
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