A) \[{{\alpha }^{2}}=\sqrt{\frac{{{K}_{a}}}{C}}\]
B) \[{{\alpha }^{2}}=\sqrt{\frac{C}{{{K}_{a}}}}\]
C) \[\alpha =\sqrt{\frac{{{K}_{a}}}{C}}\]
D) \[\alpha =\sqrt{\frac{C}{{{K}_{a}}}}\]
Correct Answer: C
Solution :
According to the Ostwald?s dilution formula \[{{\alpha }^{2}}=\frac{K(1-\alpha )}{C}\]. But for weak electrolytes a is very small. So that \[(1-\alpha )\] can be neglected. So that \[\alpha =\sqrt{\frac{{{K}_{a}}}{C}}\].
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