Answer:
\[{{K}_{\max }}=e{{V}_{0}}=1.6\times {{10}^{-19}}C\times 1.5V\] \[=24\times {{10}^{-19}}J\] or \[\mathbf{1}\mathbf{.5eV}\]
You need to login to perform this action.
You will be redirected in
3 sec
