A) \[9.28\times {{10}^{-4}}\,m\]
B) \[9.28\times {{10}^{-7}}\,m\]
C) \[9.28\times {{10}^{-8}}\,m\]
D) \[9.28\times {{10}^{-10}}\,m\]
Correct Answer: C
Solution :
Formula for de-Broglie wavelength is \[\lambda =\frac{h}{p}\] or \[\lambda =\frac{h}{mv}\Rightarrow eV=\frac{1}{2}m{{v}^{2}}\] or \[\nu =\sqrt{\frac{2eV}{m}}\] \[\lambda =\frac{h}{\sqrt{2meV}}\]\[=\frac{6.62\times {{10}^{-34}}}{\sqrt{2\times 9.1\times {{10}^{-31}}\times 2.8\times {{10}^{-23}}}}\] \[\lambda =9.28\times {{10}^{-8}}meter\].
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