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JEE Main & Advanced Physics Wave Mechanics Question Bank Doppler's Effect

  • question_answer
    A person carrying a whistle emitting continuously a note of 272 Hz is running towards a reflecting surface with a speed of 18 km/hour. The speed of sound in air is \[345m{{s}^{-1}}\]. The number of beats heard by him is  [Kerala (Engg.) 2002]

    A)            4    

    B)            6

    C)            8    

    D)            3

    Correct Answer: C

    Solution :

               According the concept of sound image \[n'=\frac{v+{{v}_{\text{person}}}}{v-{{v}_{\text{person}}}}.272=\frac{345+5}{345-5}\times 272=280\]Hz                    \[\Delta n=\]Number of beats =280 ? 272 = 8 Hz


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