JEE Main & Advanced Physics Wave Mechanics Question Bank Doppler's Effect

  • question_answer
    A source and an observer approach each other with same velocity 50 m/s. If the apparent frequency is 435 sec?1, then the real frequency is                                                    [CPMT 2003]

    A)            320 s?1                                     

    B)            360 sec?1

    C)            390 sec?1                                

    D)            420 sec?1

    Correct Answer: A

    Solution :

               \[n'=n\left[ \frac{v+{{v}_{O}}}{v-{{v}_{S}}} \right];\]Here \[v=332\]m/s  and \[{{v}_{0}}={{v}_{s}}=50\]m/s                    \[\Rightarrow \]\[435=n\left[ \frac{332+50}{332-50} \right]\Rightarrow n=321.12\,\,se{{c}^{-1}}\approx 320\,se{{c}^{1}}\]


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