A) Below both the lines
B) Above both the lines
C) In between the lines
D) None of these
Correct Answer: A
Solution :
\[L\equiv 2x+3y-4=0\], \[{{L}_{(-6,2)}}=-12+6-4<0\] \[L'=6x+9y+8=0\], \[L{{'}_{(-6,2)}}=-36+18+8<0\] Hence the point is below both the lines..You need to login to perform this action.
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