A) \[20\sqrt{2}\beta =11\alpha \]
B) \[20\sqrt{2}\alpha =11\beta \]
C) \[11\sqrt{2}\beta =20\alpha \]
D) None of these
Correct Answer: A
Solution :
Distance between lines \[-x+y=2\] and \[x-y=2\] is\[\alpha =\frac{2}{\sqrt{2}}+\frac{2}{\sqrt{2}}=2\sqrt{2}\] Distance between lines \[4x-3y=5\] and \[6y-8x=1\] is, \[\beta =\frac{1}{10}+\frac{5}{5}=\frac{11}{10}\] Therefore\[\frac{\alpha }{\beta }=\frac{2\sqrt{2}}{11/10}\Rightarrow 20\sqrt{2}\beta =11\alpha \].
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