A) \[\frac{7}{13}\]
B) \[\frac{12}{13}\]
C) \[\frac{5}{13}\]
D) \[\frac{1}{13}\]
Correct Answer: A
Solution :
Perpendicular distance of straight line \[12x+5y-7=0\] from the origin is \[\frac{12\times 0+5\times 0-7}{\sqrt{{{12}^{2}}+{{5}^{2}}}}\] = \[\left| \,\frac{-7}{13}\, \right|\,=\,\frac{7}{13}\].
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