JEE Main & Advanced Mathematics Straight Line Question Bank Distance between two lines, Perpendicular distance of the line from a point Position of point w.r.t. line

  • question_answer
    The ratio in which the line \[3x+4y+2=0\] divides the distance between \[3x+4y+5=0\] and \[3x+4y-5=0\], is

    A)            \[7:3\]                                       

    B)            3 : 7

    C)            \[2:3\]                                       

    D)            None of these

    Correct Answer: B

    Solution :

               Lines \[3x+4y+2=0\]and \[3x+4y+5=0\] are on the same side of the origin. The distance between these lines is \[{{d}_{1}}=\left| \frac{2-5}{\sqrt{{{3}^{2}}+{{4}^{2}}}} \right|=\frac{3}{5}\].                    Lines \[3x+4y+2=0\] and \[3x+4y-5=0\]are on the opposite sides of the origin. The distance between these lines is \[{{d}_{2}}=\left| \frac{2+5}{\sqrt{{{3}^{2}}+{{4}^{2}}}} \right|=\frac{7}{5}\].                    Thus \[3x+4y+2=0\] divides the distance between \[3x+4y+5=0\] and \[3x+4y-5=0\] in the ratio \[{{d}_{1}}:{{d}_{2}}\] i.e., \[3:7\].


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