JEE Main & Advanced Chemistry Chemical Bonding and Molecular Structure Question Bank Dipole moment

  • question_answer If HCl molecule is completely polarized, so expected value of dipole moment is 6.12D (deby), but experimental value of dipole moment is 1.03D. Calculate the percentage ionic character             [Kerala CET 2005]

    A)                 17          

    B)                 83

    C)                 50          

    D)                 Zero

    E)                 90

    Correct Answer: A

    Solution :

               % of ionic character =\[\frac{\text{Experimental value of dipole moment}}{\text{Expected value of dipole moment}}\]                                 \[=\frac{1.03}{6.12}\times 100=16.83%\approx 17%\]

You need to login to perform this action.
You will be redirected in 3 sec spinner