JEE Main & Advanced Chemistry Chemical Bonding and Molecular Structure Question Bank Dipole moment

  • question_answer The dipole moment of HBr is \[1.6\times {{10}^{-30}}\]cm and interatomic spacing is 1Å. The % ionic character of HBr is [MP PMT 2000]

    A)                 7             

    B)                 10

    C)                 15          

    D)                 27

    Correct Answer: B

    Solution :

               Charge of \[{{e}^{-}}=1.6\times {{10}^{-19}}\]         Dipole moment of \[HBr=1.6\times {{10}^{-30}}\]         Inter atomic spacing \[=1\text{{ }\!\!\mathrm{\AA}\!\!\text{ }}=1\times {{10}^{-10}}m\]         % of ionic character in         \[HBr=\frac{\text{dipole}\,\text{moment}\,\text{of}\,HBr\times 100}{\text{inter}\,\text{spacing}\,\text{distance}\,\times q}\]                    \[=\frac{1.6\times {{10}^{-30}}}{1.6\times {{10}^{-19}}\times {{10}^{-10}}}\times 100\]                                 \[={{10}^{-30}}\times {{10}^{29}}\times 100={{10}^{-1}}\times 100\] \[=0.1\times 100=10%\]

You need to login to perform this action.
You will be redirected in 3 sec spinner