JEE Main & Advanced Mathematics Complex Numbers and Quadratic Equations Question Bank De Moivre's theorem and Roots of unity

  • question_answer
    If  \[z={{\left( \frac{\sqrt{3}}{2}+\frac{i}{2} \right)}^{5}}+{{\left( \frac{\sqrt{3}}{2}-\frac{i}{2} \right)}^{5}}\], then [MP PET 1997]

    A) \[\operatorname{Re}(z)=0\]

    B) \[\operatorname{Im}(z)=0\]

    C) \[\operatorname{Re}(z)>0,\operatorname{Im}(z)>0\]

    D) \[\operatorname{Re}(z)>0,\operatorname{Im}(z)<0\]

    Correct Answer: B

    Solution :

    Given that \[z={{\left( \frac{\sqrt{3}}{2}+i\frac{1}{2} \right)}^{5}}+{{\left( \frac{\sqrt{3}}{2}-i\frac{1}{2} \right)}^{5}}\] \[={{\left[ \cos \left( \frac{\pi }{6} \right)+i\sin \left( \frac{\pi }{6} \right) \right]}^{5}}+{{\left[ \cos \left( \frac{\pi }{6} \right)-i\sin \left( \frac{\pi }{6} \right) \right]}^{5}}\] \[=\cos \frac{5\pi }{6}+i\sin \frac{5\pi }{6}+\cos \frac{5\pi }{6}-i\sin \frac{5\pi }{6}\]. Hence Im (z) = 0.


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