A) Transketolase
B) Aldolase
C) Phosphatase
D) Hexokinase
Correct Answer: B
Solution :
\[\underset{\text{ }\!\![\!\!\text{ 4}\,\text{Molecules }\!\!]\!\!\text{ }}{\mathop{\underset{\text{PGAL}}{\mathop{\text{3}-\text{Phosphoglyceraldehyde}}}\,}}\,\underset{Isomerase}{\mathop{\xrightarrow{Triose\,phosphate}}}\,\]\[\underset{\text{ }\!\![\!\!\text{ 4}\,\text{Molecules }\!\!]\!\!\text{ }}{\mathop{\underset{\text{(DHAP)}}{\mathop{\text{Dihydroxyacetone}\,\text{phosphate}}}\,}}\,\] \[\underset{\text{ }\!\![\!\!\text{ 2}\,\text{molecules }\!\!]\!\!\text{ }}{\mathop{\text{Dihydroxyacetone}\,\text{phosphate}}}\,+\text{3}-\underset{\text{2}\,\text{molecules}}{\mathop{\text{phosphoglyceral}}}\,\] \[\text{dehyde}\xrightarrow{\text{Aldolase}}\text{fructose}-\underset{\text{ }\!\![\!\!\text{ 2}\,\text{molecules }\!\!]\!\!\text{ }}{\mathop{\text{1,}\,\text{6}-\text{diphosphate}}}\,\]
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