A) \[C{{H}_{4}}<N{{F}_{3}}<N{{H}_{3}}<{{H}_{2}}O\]
B) \[N{{F}_{3}}<C{{H}_{4}}<N{{H}_{3}}<{{H}_{2}}O\]
C) \[N{{H}_{3}}<N{{F}_{3}}<C{{H}_{4}}<{{H}_{2}}O\]
D) \[{{H}_{2}}O<N{{H}_{3}}<N{{F}_{3}}<C{{H}_{4}}\]
Correct Answer: A
Solution :
The dipole moment of \[C{{H}_{4}}=0D,\] \[N{{F}_{3}}=0.2D,\,\,N{{H}_{3}}=1.47D\] and \[{{H}_{2}}O=1.85D\]. Therefore the correct order of the dipole moment is \[C{{H}_{4}}<N{{F}_{3}}<N{{H}_{3}}<{{H}_{2}}O\].
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