A) \[\frac{5}{40}A\]
B) \[\frac{5}{50}A\]
C) \[\frac{5}{10}A\]
D) \[\frac{5}{20}A\]
Correct Answer: B
Solution :
The diode in lower branch is forward biased and diode in upper branch is reverse biased \ \[i=\frac{5}{20+30}=\frac{5}{50}A\].
You need to login to perform this action.
You will be redirected in
3 sec
