A) \[x+{{x}^{-1}}\]
B) \[x-{{x}^{-1}}\]
C) \[\frac{1}{2}(x+{{x}^{-1}})\]
D) None of these
Correct Answer: C
Solution :
We have \[S=\sum\limits_{n=0}^{\infty }{\frac{{{(\log x)}^{2n}}}{(2n)!}=\left( \frac{{{e}^{\log x}}+{{e}^{-\log x}}}{2} \right)}=\frac{x+{{x}^{-1}}}{2}\].
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