A) \[{{C}_{6}}{{H}_{5}}OH\]
B) \[{{C}_{6}}{{H}_{5}}C{{H}_{2}}OH\]
C) \[C{{H}_{3}}C\equiv CH\]
D) \[C{{H}_{3}}NH_{3}^{+}C{{l}^{-}}\]
Correct Answer: D
Solution :
Dissociation of proton from \[C{{H}_{3}}-\overset{+}{\mathop{N}}\,{{H}_{3}}C{{l}^{-}}\] is very difficult due to -I effect of \[C{{l}^{-}}\] and \[{{N}^{+}}\] while in \[{{C}_{6}}{{H}_{5}}OH\] due to resonance stabilization of phenoxide ion proton eliminate easily similarly due to H-bonding in \[{{C}_{6}}{{H}_{5}}C{{H}_{2}}OH\] it can be eliminate and \[C{{H}_{3}}C\equiv CH\] show acidic character by triple bond by which proton can be dissociate.
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