A) \[C{{H}_{3}}COOH<{{H}_{2}}S{{O}_{4}}<{{H}_{2}}C{{O}_{3}}\]
B) \[C{{H}_{3}}COOH<{{H}_{2}}C{{O}_{3}}<{{H}_{2}}S{{O}_{4}}\]
C) \[{{H}_{2}}C{{O}_{3}}<C{{H}_{3}}COOH<{{H}_{2}}S{{O}_{4}}\]
D) \[{{H}_{2}}S{{O}_{4}}<{{H}_{2}}C{{O}_{3}}<C{{H}_{3}}COOH\]
Correct Answer: C
Solution :
Decreasing order of acidic character is \[{{H}_{2}}S{{O}_{4}}>C{{H}_{3}}COOH>{{H}_{2}}C{{O}_{3}}\]
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