JEE Main & Advanced Physics Ray Optics Question Bank Critical Thinking

  • question_answer
    If the focal length of the objective lens and the eye lens are 4 mm and 25 mm respectively in a compound microscope. The length of the tube is 16 cm. Find its magnifying power for relaxed eye position  

    A)            32.75                                       

    B)            327.5 

    C)            0.3275                                     

    D)            None of the above

    Correct Answer: B

    Solution :

                       By using \[{{m}_{\infty }}=\frac{({{L}_{\infty }}-{{f}_{o}}-{{f}_{e}})D}{{{f}_{o}}{{f}_{e}}}\]                    \[=\frac{(16-0.4-2.5)\times 25}{0.4\times 2.5}\]= 327.5


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