A) \[Si{{F}_{3}}\]
B) \[{{H}_{4}}Si{{O}_{4}}\]
C) \[{{H}_{2}}S{{O}_{4}}\]
D) \[{{H}_{2}}Si{{F}_{4}}\]
Correct Answer: B
Solution :
When silicon tetra fluoride reacts with water \[{{H}_{2}}Si{{F}_{6}}\] and \[{{H}_{4}}Si{{O}_{6}}\] are formed \[\underset{\text{Silicon tetrafluoride}}{\mathop{3Si{{F}_{4}}}}\,+\underset{\text{Water}}{\mathop{4{{H}_{2}}O}}\,\to 2{{H}_{2}}Si{{F}_{6}}+\underset{\text{White silicic acid}}{\mathop{{{H}_{4}}Si{{O}_{4}}}}\,\]
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