• # question_answer The oxide, which cannot act as a reducing agent, is  [Pb. CET 2002] A) $N{{O}_{2}}$ B) $S{{O}_{2}}$ C) $C{{O}_{2}}$ D) $Cl{{O}_{2}}$

Correct Answer: C

Solution :

Reduction is accompanied by an increase in oxidation number of the reducing agent. C belong to IVA so the max-O.N. is +4. In $C{{O}_{2}}$ the oxidation number of C is +4, which cannot be further increased. Hence, $C{{O}_{2}}$can not act as reducing agent.

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