• # question_answer $M{{n}^{++}}$ can be converted into $M{{n}^{7+}}$ by reacting with [UPSEAT 2003] A) $S{{O}_{2}}$ B) $C{{l}_{2}}$ C) $Pb{{O}_{2}}$ D) $SnC{{l}_{2}}$

Strong oxidising agents such as $Pb{{O}_{2}}$ or sodium bismulthate $(NaBi{{O}_{3}})$ oxidise $M{{n}^{2+}}$ to $MnO_{4}^{-}$ or $M{{n}^{7+}}$.