A) \[2.15\times {{10}^{-11}}erg\]
B) \[0.1911\times {{10}^{-10}}erg\]
C) \[2.389\times {{10}^{-12}}erg\]
D) \[0.239\times {{10}^{-10}}erg\]
Correct Answer: B
Solution :
According to Bohr?s model \[\Delta E={{E}_{1}}-{{E}_{3}}\] \[=2.179\times {{10}^{-11}}-\frac{2.179\times {{10}^{11}}}{9}\] \[=\frac{8}{9}\times 2.179\times {{10}^{-11}}\]\[=1.91\times {{10}^{-11}}\]\[=0.191\times {{10}^{-10}}erg\] Since electron is going from \[n=1\] to \[n=3\] hence energy is absorbed.
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