A) 0.2 A
B) 0.4 A
C) Zero
D) 0.1 A
Correct Answer: A
Solution :
Since diode in upper branch is forward biased and in lower branch is reversed biased. So current through circuit \[i=\frac{V}{R+{{r}_{d}}}\]; here \[{{r}_{d}}\]= diode resistance in forward biasing = 0 Þ \[i=\frac{V}{R}=\frac{2}{10}=0.2A\].You need to login to perform this action.
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