JEE Main & Advanced Physics Wave Mechanics Question Bank Critical Thinking

  • question_answer
    Two identical flutes produce fundamental notes of frequency 300 Hz at \[{{27}^{o}}\]C. If the temperature of air in one flute is increased to \[{{31}^{o}}\]C, the number of the beats heard per second will be                                            [UPSEAT 2002]

    A)            1    

    B)            2

    C)            3    

    D)            4

    Correct Answer: B

    Solution :

                Velocity of sound increases if the temperature increases. So with \[v=n\lambda \], if \[v\] increases \[n\] will increase                    at \[{{27}^{o}}C,\,{{v}_{1}}=n\lambda \], at \[{{31}^{o}}C\,,\,\,{{v}_{2}}=(n+x)\lambda \]                    Now using \[v\propto \sqrt{T}\]            \[\left( \because v=\sqrt{\frac{\gamma RT}{M}} \right)\] \[\frac{{{v}_{2}}}{{{v}_{1}}}=\sqrt{\frac{{{T}_{2}}}{{{T}_{1}}}}=\frac{n+x}{n}\] Þ \[\frac{300+x}{300}=\sqrt{\frac{(273+31)}{(273+27)}}=\sqrt{\frac{304}{300}}=\sqrt{\frac{300+4}{300}}\] Þ \[1+\frac{x}{300}={{\left( 1+\frac{4}{300} \right)}^{1/2}}=\left( 1+\frac{1}{2}\times \frac{4}{300} \right)\,\]Þ x = 2. \[[\because {{(\,1+x)}^{n}}=1+nx]\]


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