• # question_answer $C{{H}_{3}}C\equiv CC{{H}_{3}}\underset{(ii){{H}_{2}}O/Zn}{\mathop{\xrightarrow{(i)\text{ }X}}}\,\underset{\,O\,\,\,\,\,\,O\,}{\mathop{\underset{|\,\,\,\,\,\,\,\,\,\,\,\,\,|}{\mathop{C{{H}_{3}}-C-C-C{{H}_{3}}}}\,}}\,$ X in the above reaction is [CPMT 1985; MP PET 1997; Roorkee Qualifying 1998; DPMT 2001] A) $HN{{O}_{3}}$ B) ${{O}_{2}}$ C) ${{O}_{3}}$ D) $KMn{{O}_{4}}$

$C{{H}_{3}}-C\equiv C-C{{H}_{3}}\underset{\text{(ii)}\,Zn/{{H}_{2}}O}{\mathop{\xrightarrow{\text{(i)}\,{{O}_{3}}}}}\,C{{H}_{3}}-\underset{O}{\mathop{\underset{||}{\mathop{C}}\,}}\,-\underset{O}{\mathop{\underset{||}{\mathop{C}}\,}}\,-C{{H}_{3}}$