A) \[HN{{O}_{3}}\]
B) \[{{O}_{2}}\]
C) \[{{O}_{3}}\]
D) \[KMn{{O}_{4}}\]
Correct Answer: C
Solution :
\[C{{H}_{3}}-C\equiv C-C{{H}_{3}}\underset{\text{(ii)}\,Zn/{{H}_{2}}O}{\mathop{\xrightarrow{\text{(i)}\,{{O}_{3}}}}}\,C{{H}_{3}}-\underset{O}{\mathop{\underset{||}{\mathop{C}}\,}}\,-\underset{O}{\mathop{\underset{||}{\mathop{C}}\,}}\,-C{{H}_{3}}\]
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