A) 1/4
B) 4
C) 1/2
D) 2
Correct Answer: D
Solution :
\[E=hv=h\frac{c}{\lambda }\,\] i.e. \[E\propto \frac{1}{\lambda }\] \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{\lambda }_{2}}}{{{\lambda }_{1}}}=\frac{4000}{2000}=2.\]
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