A) 5
B) 50
C) 500
D) 0.5
Correct Answer: B
Solution :
The slope of anode characteristic curve \[=\frac{1}{{{r}_{p}}}\] \[\Rightarrow {{r}_{p}}=\frac{1}{0.02\,mA/V}=50\frac{V}{mA}=50\times {{10}^{3}}\frac{V}{A}\] The slope of mutual characteristic curve = gm = 1 ´ 10?3 A/V. \[\therefore \mu ={{r}_{p}}\times {{g}_{m}}=50\times {{10}^{3}}\times {{10}^{-3}}=50\].
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