A) 14
B) 13
C) 6
D) 9
Correct Answer: C
Solution :
Critical hearing frequency for a person is 20,000Hz. If a closed pipe vibration in \[{{N}^{th}}\] mode then frequency of vibration \[n=\frac{(2N-1)v}{4l}=(2N-1){{n}_{1}}\] (where \[{{n}_{1}}=\]fundamental frequency of vibration) Hence 20,000 \[=(2N-1)\times 1500\] Þ \[N=7.1\approx 7\] Also, in closed pipe Number of over tones = (No. of mode of vibration) ?1 = 7 ? 1 = 6.You need to login to perform this action.
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