A) \[\cos kx\sin \omega \,t\]
B) \[{{k}^{2}}{{x}^{2}}-{{\omega }^{2}}{{t}^{2}}\]
C) \[\cos (kx+\omega \,t)\]
D) \[\cos ({{k}^{2}}{{x}^{2}}-{{\omega }^{2}}{{t}^{2}})\]
Correct Answer: C
Solution :
\[y=\cos kx\sin \omega \,t\] and \[y=\cos (kx+\omega \,t)\] represent wave motion, because they satisfies the wave equation \[\frac{{{\partial }^{2}}}{\partial {{t}^{2}}}={{v}^{2}}\frac{{{\partial }^{2}}y}{\partial {{x}^{2}}}\].
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