A) \[\sin \omega t-\cos \omega t\]
B) \[{{\sin }^{2}}\omega t\]
C) \[\sin \omega x+\sin 2\omega t\]
D) \[\sin \omega x-\sin 2\omega t\]
Correct Answer: A
Solution :
The standard differential equation is satisfied by only the function \[\sin \omega \,t-\cos \omega \,t.\]Hence it represents S.H.M.
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