A) \[{{H}_{5}}{{C}_{6}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-H\]
B) \[{{H}_{5}}{{C}_{6}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-{{C}_{6}}{{H}_{5}}\]
C) \[{{H}_{5}}{{C}_{6}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-C{{H}_{3}}\]
D) \[{{H}_{5}}{{C}_{6}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-C{{H}_{2}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-C{{H}_{3}}\]
Correct Answer: C
Solution :
\[\underset{\text{(Keto}\,\text{form)}}{\mathop{{{C}_{6}}{{H}_{5}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-C{{H}_{3}}}}\,\,\text{and}\,\underset{\text{(enol form)}}{\mathop{{{C}_{6}}{{H}_{5}}-\overset{OH}{\mathop{\overset{|\,\,\,\,\,\,}{\mathop{C=}}\,}}\,}}\,C{{H}_{2}}\] \[\underset{\text{(Keto form)}}{\mathop{{{C}_{6}}{{H}_{5}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-C{{H}_{2}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-C{{H}_{3}}}}\,\,\]and \[\underset{\text{(enol form)}}{\mathop{{{C}_{6}}{{H}_{5}}-\underset{O}{\mathop{\underset{||}{\mathop{C}}\,}}\,-CH=\underset{OH}{\mathop{\underset{|\,\,\,\,}{\mathop{C\,\,\,}}\,}}\,-C{{H}_{3}}}}\,\]
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