• # question_answer Which of the following is in the increasing order of the ionic character [JIPMER 2002] A) $PbC{{l}_{4}}<PbC{{l}_{2}}<CaC{{l}_{2}}<NaCl$ B) $PbC{{l}_{2}}<PbC{{l}_{4}}<CaC{{l}_{2}}<NaCl$ C) $PbC{{l}_{2}}<PbC{{l}_{4}}<NaCl<CaC{{l}_{2}}$ D) $PbC{{l}_{4}}<PbC{{l}_{2}}<NaCl<CaC{{l}_{2}}$

Correct Answer: A

Solution :

$PbC{{l}_{4}}<PbC{{l}_{2}}<CaC{{l}_{2}}<NaCl$ is the increasing order of ionic character.

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