2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Semiconducting Devices

JEE Main & Advanced Physics Semiconducting Devices Question Bank Critical Thinking

  • question_answer
    In PN-junction diode the reverse saturation current is \[{{10}^{-5}}\]amp at\[27{}^\circ C.\] The forward current for a voltage of  \[0.2volt\] is                                                   [MP PMT 1993]

    A)            \[2037.6\times {{10}^{-3}}amp\]                                     

    B)            \[203.76\times {{10}^{-3}}amp\]

    C)            \[20.376\times {{10}^{-3}}amp\]                                     

    D)            \[2.0376\times {{10}^{3}}amp\] \[[\exp (7.62)=2038.6,\,K=1.4\times {{10}^{-23}}J/K]\]

    Correct Answer: C

    Solution :

                       The forward current \[i={{i}_{s}}\,({{e}^{eV/kT}}-1)={{10}^{-5}}\,\left[ {{e}^{\frac{1.6\times {{10}^{-19}}\times \,0.2}{1.4\times {{10}^{-23}}\times \,300}}}-1 \right]\] \[={{10}^{-5}}\,[2038.6-1]=20.376\times {{10}^{-3}}A\]


You need to login to perform this action.
You will be redirected in 3 sec spinner