A) \[{{10}^{-3}}\]
B) \[{{10}^{-4}}\]
C) \[{{10}^{-5}}\]
D) \[{{10}^{-6}}\]
Correct Answer: A
Solution :
\[{{K}_{a}}=1.0\times {{10}^{-5}}\] \[{{K}_{h}}=\text{hydrolysis}\,\,\text{constant}\] \[{{K}_{h}}=\frac{{{K}_{w}}}{{{K}_{a}}}=\frac{{{10}^{-14}}}{{{10}^{-5}}}={{10}^{-9}}\] degree of hydrolysis (h ) =\[\sqrt{\frac{{{K}_{h}}}{C}}\] \[=\sqrt{\frac{{{10}^{-9}}}{0.001}}\] =\[\sqrt{{{10}^{-6}}}\] =\[{{10}^{-3}}\]; \[h={{10}^{-3}}\]
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